Examen de Quimica . Yatziri Lilian Hernandez Lopez 271 a.

4 Fe Cl² + 2 Cl² ⟶ 4 Fe Cl ³
DATOS:
Fe =4 × 56= 224
Cl = 15 × 35 =420 =644 g/mol
Cl = 4 × 35 =140
4 × 56 =224
8 × 35 =280 =504 g/mol

X = (900 g Fe Cl ³ ×140)/504 = 250

X =(900 g Fe Cl ³ ×644 g)/504 = 1150